Syntax
VAR_POP([ALL] expr) OVER over_clause
Purpose
You can call this function to return the population variance of the expr expression.
If no matching row is found, it returns NULL.
Examples
obclient> CREATE TABLE EMPLOYEES (MANAGER_ID INT,LAST_NAME VARCHAR(50),HIREDATE VARCHAR(50),SALARY INT);
INSERT INTO EMPLOYEES VALUES(100, 'RAPHAELY', '2017-07-01', 1700);
INSERT INTO EMPLOYEES VALUES(100, 'DE HAAN', '2018-05-01',11000);
INSERT INTO EMPLOYEES VALUES(100, 'ERRAZURIZ', '2017-07-21', 1400);
INSERT INTO EMPLOYEES VALUES(100, 'HARTSTEIN', '2019-05-01',14000);
INSERT INTO EMPLOYEES VALUES(100, 'RAPHAELY', '2017-07-22', 1700);
INSERT INTO EMPLOYEES VALUES(100, 'WEISS', '2019-07-11',13500);
INSERT INTO EMPLOYEES VALUES(100, 'RUSSELL', '2019-10-05', 13000);
INSERT INTO EMPLOYEES VALUES(100, 'PARTNERS', '2018-12-01',14000);
INSERT INTO EMPLOYEES VALUES(200, 'ROSS', '2019-06-11',13500);
INSERT INTO EMPLOYEES VALUES(200, 'BELL', '2019-05-25', 13000);
INSERT INTO EMPLOYEES VALUES(200, 'PART', '2018-08-11',14000);
COMMIT;
obclient> SELECT LAST_NAME,SALARY,VAR_POP(SALARY) OVER(ORDER BY HIREDATE) AS DEVISION FROM EMPLOYEES WHERE MANAGER_ID = 100;
+-----------+--------+-------------------+
LAST_NAME SALARY DEVISION
+-----------+--------+-------------------+
RAPHAELY 1700 0
ERRAZURIZ 1400 22500
RAPHAELY 1700 20000
DE HAAN 11000 16582500
PARTNERS 14000 29426400
HARTSTEIN 14000 33500000
WEISS 13500 33421224.48979592
RUSSELL 13000 31778593.75
+-----------+--------+-------------------+
8 rows in set (0.00 sec)